3(x+y^2)+5(2x-y)=

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Solution for 3(x+y^2)+5(2x-y)= equation:


Simplifying
3(x + y2) + 5(2x + -1y) = 0
(x * 3 + y2 * 3) + 5(2x + -1y) = 0
(3x + 3y2) + 5(2x + -1y) = 0
3x + 3y2 + (2x * 5 + -1y * 5) = 0
3x + 3y2 + (10x + -5y) = 0

Reorder the terms:
3x + 10x + -5y + 3y2 = 0

Combine like terms: 3x + 10x = 13x
13x + -5y + 3y2 = 0

Solving
13x + -5y + 3y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '5y' to each side of the equation.
13x + -5y + 5y + 3y2 = 0 + 5y

Combine like terms: -5y + 5y = 0
13x + 0 + 3y2 = 0 + 5y
13x + 3y2 = 0 + 5y
Remove the zero:
13x + 3y2 = 5y

Add '-3y2' to each side of the equation.
13x + 3y2 + -3y2 = 5y + -3y2

Combine like terms: 3y2 + -3y2 = 0
13x + 0 = 5y + -3y2
13x = 5y + -3y2

Divide each side by '13'.
x = 0.3846153846y + -0.2307692308y2

Simplifying
x = 0.3846153846y + -0.2307692308y2

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